6(x^2+2x)^2+1=-5(x^2+2x)

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Solution for 6(x^2+2x)^2+1=-5(x^2+2x) equation: 



6(x^2+2x)^2+1=-5(x^2+2x)

We move all terms to the left:

6(x^2+2x)^2+1-(-5(x^2+2x))=0



We calculate terms in parentheses: -(-5(x^2+2x)), so:

-5(x^2+2x)

We multiply parentheses

-5x^2-10x

Back to the equation:

-(-5x^2-10x)



We get rid of parentheses

5x^2+10x+6(x^2+2x)^2+1=0

We move all terms containing x to the left, all other terms to the right

5x^2+10x+6(x^2+2x)^2=-1

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